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Laws of indices (exponents)

Multiply, divide and raise powers; work with zero, negative and fractional indices.

Also known as: exponent rules, powers, negative indices, fractional indices.

Key ideas

  • am×an=am+na^m \times a^n = a^{m+n} and am÷an=am−na^m \div a^n = a^{m-n}.
  • (am)n=amn(a^m)^n = a^{mn} and (ab)n=anbn(ab)^n = a^n b^n.
  • a0=1a^0 = 1 and a−n=1ana^{-n} = \frac{1}{a^n} (for a≠0a \neq 0).
  • am/n=(an)ma^{m/n} = \left(\sqrt[n]{a}\right)^m.

The core laws

Powers with the same base combine by adding or subtracting indices: x4×x3=x7,x9x2=x7.x^4 \times x^3 = x^7, \qquad \frac{x^9}{x^2} = x^7. A power of a power multiplies: (x3)4=x12(x^3)^4 = x^{12}. Every factor inside a bracket is raised: (3a2b)3=27a6b3(3a^2b)^3 = 27a^6b^3.

Zero and negative indices

Any non-zero number to the power 00 equals 11. A negative index means a reciprocal: 4−1=14,2−3=18,(23)−2=94.4^{-1} = \frac{1}{4}, \qquad 2^{-3} = \frac{1}{8}, \qquad \left(\frac{2}{3}\right)^{-2} = \frac{9}{4}.

Fractional indices and equations

The denominator is a root and the numerator is a power: 272/3=(273)2=927^{2/3} = (\sqrt[3]{27})^2 = 9. Take the root first to keep numbers small.

To solve 2x+3=8x−12^{x+3} = 8^{x-1}, write both sides with the same base: 8=238 = 2^3, so 2x+3=23x−32^{x+3} = 2^{3x-3} and x+3=3x−3x + 3 = 3x - 3, giving x=3x = 3.

Worked examples

Example 1 · Fractional and negative index

Evaluate (1681)−3/4\left(\frac{16}{81}\right)^{-3/4}.

  1. Step 1.Negative index: flip the fraction → (8116)3/4\left(\frac{81}{16}\right)^{3/4}.
  2. Step 2.Fourth root: 32\frac{3}{2}.
  3. Step 3.Cube: 278\frac{27}{8}.

Answer: 278\frac{27}{8}

Example 2 · Equation with powers

Solve 2x+3=8x−12^{x+3} = 8^{x-1}.

  1. Step 1.8x−1=(23)x−1=23x−38^{x-1} = (2^3)^{x-1} = 2^{3x-3}.
  2. Step 2.Equate indices: x+3=3x−3x + 3 = 3x - 3.
  3. Step 3.x=3x = 3.

Answer: x=3x = 3

Common mistakes

  • Multiplying indices when multiplying powers: x4×x3≠x12x^4 \times x^3 \neq x^{12}.
  • Thinking a negative index makes the number negative: 2−3=182^{-3} = \frac{1}{8}, not −8-8.
  • Forgetting to raise the coefficient: (3a2)3=27a6(3a^2)^3 = 27a^6, not 3a63a^6.

Try it yourself

Original practice questions. Your answer is checked instantly.

Question 1Laws of indices (exponents)Easier

Which expression is equivalent to x4⋅x3x^4 \cdot x^3?

Question 2Laws of indices (exponents)Easier

Evaluate 50+4−15^0 + 4^{-1}.

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